i see. thanks! -Anthony. On Mon, May 26, 2003 at 12:39:53PM +1000, Tim Robbins wrote: > On Sun, May 25, 2003 at 05:17:30PM -0400, Anthony Schneider wrote: > > > so, does this mean that mpich somehow exhausted all shmem locks? > > after running the program only 10 times, i see this as infeasible, > > considering > > a) mpich (presumably in MPI_Init()) would only want 1 or > > 2 locks on init > > and > > b) any shared memory locks mpich grabs should be freed > > upon process completion (whether clean or not) by the > > operating system, no? > > No, semaphores stay around until they are removed. Perhaps there's an MPI_Xyz > function you should be calling before your program exits. In any case, you can > use "ipcs -s" to list semaphores, and "ipcrm -s semid" to remove semaphores. > > It looks like the program is leaking semaphores -- notice how your program > fails when you run it for the 11th time, and the default maximum number of > semaphores in the GENERIC kernel is 10 (sysctl kern.ipc.semmni). > > > Tim
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