Has anyone else tried out the most basic IPv6 test: ndp -I <iface> and then ping6 fe80::<normal address without %<iface> extension>? I was greeted by recursion on a non-recursive lock. After some sleuthing, I tried to determine what conditions could be tested for that would indicate "this must not call the nd6_is_addr_neighbor() call because we're from a normal RTM_RESOLVE initializing a new route", and this is the most correct thing I can come up with. It actually would do something entirely different if recursion were allowed. Comments? Index: nd6.c =================================================================== RCS file: /u/FreeBSD-cvs/src/sys/netinet6/nd6.c,v retrieving revision 1.37 diff -u -r1.37 nd6.c --- nd6.c 8 Nov 2003 23:36:32 -0000 1.37 +++ nd6.c 26 Nov 2003 13:45:45 -0000 _at__at_ -1095,7 +1095,8 _at__at_ if (req == RTM_RESOLVE && (nd6_need_cache(ifp) == 0 || /* stf case */ - !nd6_is_addr_neighbor((struct sockaddr_in6 *)rt_key(rt), ifp))) { + ((!(rt->rt_flags & RTF_WASCLONED) || rt->rt_flags & RTF_LLINFO) && + !nd6_is_addr_neighbor((struct sockaddr_in6 *)rt_key(rt), ifp)))) { /* * FreeBSD and BSD/OS often make a cloned host route based * on a less-specific route (e.g. the default route).Received on Wed Nov 26 2003 - 09:46:19 UTC
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