Re: Number of significand bits in long double?

From: Bakul Shah <bakul_at_BitBlocks.com>
Date: Thu, 04 Aug 2005 10:08:14 -0700
> PROPERTIES OF LONG DOUBLE
> Base = 2
> Significant base digits = 53 (= at least 15 decimal digits)

$ cat x.c
#include <machine/float.h>
static double x = DBL_MAX;
static long double min = LDBL_MIN;
static long double max = LDBL_MAX;

$ gcc -S x.c

$ cat x.s
        .file   "x.c"
        .data
        .p2align 3
        .type   x, _at_object
        .size   x, 8
x:
        .long   -1
        .long   2146435071
        .p2align 4
        .type   min, _at_object
        .size   min, 12
min:
        .long   0
        .long   -2147483648
        .long   1
        .p2align 4
        .type   max, _at_object
        .size   max, 12
max:
        .long   0
        .long   -2147483648
        .long   32767
        .ident  "GCC: (GNU) 3.4.4 [FreeBSD] 20050518"

So this indicates long double is 15 bits of exponent, 64 bits of mantissa.
Received on Thu Aug 04 2005 - 15:08:15 UTC

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