On Sun, Nov 12, 2006 at 04:11:51PM +0100, Giorgos Keramidas wrote: > On 2006-11-12 17:51, Ruslan Ermilov <ru_at_FreeBSD.org> wrote: > > On Sun, Nov 12, 2006 at 03:42:30PM +0100, Giorgos Keramidas wrote: > > > On 2006-11-12 17:00, Ruslan Ermilov <ru_at_freebsd.org> wrote: > > > > %%% > > > > $ cat a.c > > > > struct foo { > > > > char x; > > > > }; > > > > > > > > struct foo * > > > > bubu(char *s) > > > > { > > > > > > > > return (struct foo *)s; > > > > } > > > > $ cc -c -Wcast-align a.c > > > > a.c: In function `bubu': > > > > a.c:9: warning: cast increases required alignment of target type > > > > %%% > > > > > > > > (None of other supported architecutes see the issue here.) > > > > > > You can't cast any random (char *) pointer to a pointer of a type which > > > is (potentially) larger than 1 byte. It's the same sort of warning you > > > will get if you try to: > > > > > > char ch[] = "\x00\x00\x00\x00"; > > > char *p = &(ch[0]); > > > unsigned long *lptr = (unsigned long *)p; > > > > > > You cannot guarantee that `ch' is stored in an address that is properly > > > aligned for (unsigned long), and this is what GCC warns about here. > > > > No, your example I perfectly understand but it is completely different. > > Note that the first (and only) member in my structure is "char", so it > > doesn't need to be more than sizeof(char) aligned. > > Ah, but the tricky part is that inside bubu() there is no knowledge that > `s' may be properly aligned for a (struct foo *) pointer. All the > compiler knows is that it is a (char *), possibly misaligned for any > pointer whose object has a size > 1. > I don't think you're right. If I don't declare a structure so that the compiler REALLY doesn't know the alignment requirement, it doesn't even complain (this is on ARM): : $ diff -u20 a.c b.c : --- a.c Sun Nov 12 18:19:34 2006 : +++ b.c Sun Nov 12 18:19:22 2006 : _at__at_ -1,10 +1,12 _at__at_ : #include <stdio.h> : : -struct foo; : +struct foo { : + char x; : +}; : : struct foo * : bubu(char *s) : { : : return (struct foo *)s; : } : $ cc -c -Wcast-align a.c : $ cc -c -Wcast-align b.c : b.c: In function `bubu': : b.c:11: warning: cast increases required alignment of target type > > > On 2006-11-12 15:27, Stefan Farfeleder <stefan_at_fafoe.narf.at> wrote: > > > > What is sizeof(struct foo)? If it's > 1 it makes sense. > > > > > > Exactly :) > > > > Still doesn't make much sense to me. If all structure members are chars > > (like is the case with "struct ar_hdr" from <ar.h> which GCC complains > > about, and in my example, the required alignment shouldn't be more than > > sizeof(char). What am I missing? > > You are missing that inside bubu() the compiler 'believes' that: > > * The `s' pointer is (char *)-aligned. > > * The sizeof(struct foo) is >1. > > * You are trying to assign `s' (with it's possibly misaligned > value) to the `return value' place, whose type is (at > least, as far as the compiler knows) is (struct foo *). > I will assume that under a "misaligned value" you mean a data that the `s' pointer points to. Assigning a pointer to pointer isn't a problem per se, there are no alignment issues here; dereferencing an assigned pointer later might be a problem if it points to an object with more strict alignment requirement. This is all clear and fine, I understand how all this works. :-) What I don't seem to understand (and you didn't tell me) is why the alignment requirement for "struct foo" is >1. From the above it looks like you're thinking that __alignof__(x) >= sizeof(x). Fortunately, not all that bad, and compiling the following snippet on sparc64: : #include <stdio.h> : : struct foo1 { : char foo[4]; : }; : : struct foo2 { : int foo; : }; : : int : main(char *s) : { : struct foo1 *foo1 = (struct foo1 *)s; : struct foo2 *foo2 = (struct foo2 *)s; : printf("%jd %jd\n", __alignof__(*foo1), __alignof__(*foo2)); : } Only complains about the second assignment: : a.c: In function `main': : a.c:15: warning: cast increases required alignment of target type Running it outputs: "1 4". Similarly for "struct ar_hdr", whose all members are character arrays, also has the alignment requirement of 1 byte (verified on sparc64). So your sizeof() argument, well... I don't understand it and it doesn't make things clearer at least to me. I still believe this is bug in GCC that the alignment requirement is so high for a "struct foo { char x; }" (there's no real reason for this!). Cheers, -- Ruslan Ermilov ru_at_FreeBSD.org FreeBSD committer
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