On Mon, 17 Sep 2007, Maxim Sobolev wrote: MS> > possibly stupid question: it there a way to fool jail (real, not MS> > "tinderbox" one) that it's working under i386 kernel? This would be MS> > extremely useful for local package building. MS> > MS> > Quick googling does not reveal anything, or did I miss something obvious? MS> > MS> > Thanks in advance. MS> MS> Works here like a charm. The only thing is that you need to set UNAME_p=i386 MS> UNAME_m=i386 and CPUTYPE=i686 variables in the chroot/jail. I know aboot uname tricks ;-) What about sysctls revealing amd64 system internals? Did you compare packages built by this jailed system with native? Sincerely, D.Marck [DM5020, MCK-RIPE, DM3-RIPN] [ FreeBSD committer: marck_at_FreeBSD.org ] ------------------------------------------------------------------------ *** Dmitry Morozovsky --- D.Marck --- Wild Woozle --- marck_at_rinet.ru *** ------------------------------------------------------------------------Received on Mon Sep 17 2007 - 19:15:02 UTC
This archive was generated by hypermail 2.4.0 : Wed May 19 2021 - 11:39:17 UTC