Re: i386 package building on an amd64 system

Dmitry Morozovsky writes:
| Hi there colleagues,
|
| possibly stupid question: it there a way to fool jail (real, not "tinderbox"
| one) that it's working under i386 kernel? This would be extremely useful for
| local package building.
|
| Quick googling does not reveal anything, or did I miss something obvious?

Mostly,
        OSVERSION=
        UNAME_m=
        UNAME_p=
        UNAME_r=
        UNAME_s=
        UNAME_v=
then chroot or jail.  I have a script:

#!/bin/sh

UNAME_s="FreeBSD"
UNAME_m="i386"
UNAME_p="i386"
ROOT=$HOME/current_$UNAME_p
REVISION=`cd ${ROOT}/sys/conf && grep REVISION= newvers.sh | cut -f2 -d'"'`
BRANCH=`cd ${ROOT}/sys/conf && grep BRANCH= newvers.sh | head -n1 |  cut -f2 -d'
"'`
UNAME_r=$REVISION-$BRANCH
UNAME_v="$UNAME_s $UNAME_r #0: Thu May  4 07:54:55 PDT 2006     root_at_a21p:/data/
home/ambrisko/current/usr/src/sys/$UNAME_p/compile/THINK"
OSVERSION=`awk '/\#define.*__FreeBSD_version/ { print $3 }' < ${ROOT}/sys/sys/pa
ram.h`
export UNAME_s UNAME_r UNAME_v UNAME_m UNAME_p OSVERSION ROOT
if [ -r $ROOT/dev/zero ]
then
        echo dev already mounted
else
        sudo mount -t devfs dev $ROOT/dev
fi
sudo ln -sf ld-elf.so.1 $ROOT/libexec/ld-elf32.so.1
sudo sh -c '( echo "libpthread.so.2 libthr.so.2" ;\
        echo "libpthread.so libthr.so") > ${ROOT}/etc/libmap.conf'
sudo cp ${ROOT}/etc/libmap.conf ${ROOT}/etc/libmap32.conf
sudo chroot $ROOT

It could be made even smarter but looking at the dest and figuring out 
the release as well.

We could make it a make target since you can do this into 6.2 world as
well (amd64/current -> amd64/6.2, amd64/current -> i386/6.2 or
amd64/current -> amd64/i386).  I think I merged in the UNAME_/OSVERSION
stuff before 6.2 went out.  I also have local hacks to do this with 4.X.

At work, our build machines are all loaded up with amd64 and we build
i386 or amd64 SW on them.  This includes whatever ports are needed.

Doug A.