Hello, I have tried to create a kernel for my dual CPU motherboard: Intel Pentium III (801.82-MHz 686-class CPU) But what is the command that proofs to me that both CPUs are indeed recognized and in use. Is it the dmesg output, or mptable command? # mptable [...cut...] Processors: APIC ID Version State Family Model Step Flags 1 0x11 BSP, usable 6 8 6 0x387fbff 0 0x11 AP, usable 6 8 6 0x383fbff [...cut...] # cat /var/run/dmesg.boot FreeBSD 5.3-STABLE #0: Thu Oct 28 07:59:10 KST 2004 lahaye_at_master.snu.ac.kr:/usr/obj/usr/src/sys/MYKERNEL MPTable: <OEM00000 PROD00000000> Timecounter "i8254" frequency 1193182 Hz quality 0 CPU: Intel Pentium III (801.82-MHz 686-class CPU) Origin = "GenuineIntel" Id = 0x686 Stepping = 6 Features=0x383fbff<FPU,VME,DE,PSE,TSC,MSR,PAE,MCE,CX8,APIC,SEP,MTRR,PGE,MCA,CMOV,PAT,PSE36,MMX, FXSR,SSE> real memory = 1073729536 (1023 MB) avail memory = 1045377024 (996 MB) ioapic0: Assuming intbase of 0 ioapic0 <Version 1.1> irqs 0-23 on motherboard npx0: [FAST] npx0: <math processor> on motherboard npx0: INT 16 interface [...cut...] So? Am I there? Is my FreeBSD now running on two processors? With the top command, I can't see anything special for my 2 CPUs. Is that right? Rob.Received on Thu Oct 28 2004 - 10:48:13 UTC
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