On Monday 31 July 2006 16:46, Christian S.J. Peron wrote: > Robert Huff wrote: > > Yar Tikhiy writes: > > > > > >> FWIW, the LOR still is there. I was seeing it yesterday while > >> fiddling with the ipfw and natd rc.d scripts. > >> > >> lock order reversal: > >> 1st 0xc1a36090 inp (divinp) _at_ /usr/src/sys/modules/ipdivert/../../netinet/ip_divert.c:350 > >> 2nd 0xc0a51918 PFil hook read/write mutex (PFil hook read/write mutex) _at_ /usr/src/sys/net/pfil.c:73 > >> > > > > For the record, I'm (still) getting this also. > > > > > > Robert Huff > > _______________________________________________ > > freebsd-current_at_freebsd.org mailing list > > http://lists.freebsd.org/mailman/listinfo/freebsd-current > > To unsubscribe, send any mail to "freebsd-current-unsubscribe_at_freebsd.org" > > > > > > > > This appears to be similar to the LOR associated with IPFW and ucred > based rules, I think. Although this is a lock order reversal and it > probably isn't a false positive, it should be reasonably harmless, > because the pfil hook lock is a reader lock, thus different threads can > acquire it (at this point) con-currently, presumably preventing a dead > lock from actually occurring here. > > iirc witness it not aware of the reader/writer semantics, so it makes > sense that it will be dropping a warning here. But I can look at this in > further detail when I get a bit of time. No, a LOR is a LOR. Readers vs writers don't matter for ordering reasons. Talk yourself through it and you'll see. The reason is that a writer can always block on a reader, and a reader will block if there's a writer already holding the lock. While you can end up in some situations where a LOR might not deadlock at the time if both threads involved are getting read locks, at some point a thread will need to get a write lock (otherwise you wouldn't need a lock!) and then you can get a deadlock between the thread with the write lock and a thread acquiring the locks in reverse order even if that second thread is only getting a read lock. Specifically, given mtx A, and rwlock B, while it may be safe for a thread to rlock B and lock A while another thread does lock A and rlock B w/o triggering deadlock, if a thread does lock A and then wlock B, then when another tried tries to rlock B and then lock A you will get deadlock. -- John BaldwinReceived on Tue Aug 01 2006 - 13:45:44 UTC
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