Re: CALL for TEST [HOSTAP] run(4) ralink usb wireless

AK-san,

PseudoCylon wrote:
>> Thank you very much.
>> However it  still panics when I tried to use bridge.
>>     
>
>
> Please try this.
> http://gitorious.org/run/run/trees/master/dev/usb/wlan
> (if_run.c and if_runvar.h have been updated.)
>
> Sorry I haven't test on bridge (only with nat). It did panic with bridge. This should work. But, please
> #sysctl hw.usb.run.debug=1
> just in case.
>   

Thanks a lot, works no problem so far here with bridge (no
auth/hostapd/WPA2).

rspro# uname -an
FreeBSD rspro 9.0-CURRENT FreeBSD 9.0-CURRENT #64 r207140M: Mon May  3
21:49:50 ULAT 2010    
tsgan_at_beastie:/usr/obj/mips/usr/mysrc/sys/RSPRO_AR71XX  mips

...
wlan0: STA 00:26:bb:17:f6:61 IEEE 802.11: associated
  New STA
wlan0: STA 00:26:bb:17:f6:61 WPA: event 1 notification
bsd_del_key: addr=00:26:bb:17:f6:61 key_idx=0

wlan0: STA 00:26:bb:17:f6:61 WPA: start authentication
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state INITIALIZE
bsd_del_key: addr=00:26:bb:17:f6:61 key_idx=0

bsd_set_sta_authorized: addr=00:26:bb:17:f6:61 authorized=0

wlan0: STA 00:26:bb:17:f6:61 IEEE 802.1X: unauthorizing port
WPA: 00:26:bb:17:f6:61 WPA_PTK_GROUP entering state IDLE
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state AUTHENTICATION
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state AUTHENTICATION2
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state INITPSK
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state PTKSTART
wlan0: STA 00:26:bb:17:f6:61 WPA: sending 1/4 msg of 4-Way Handshake
WPA: Send EAPOL(version=2 secure=0 mic=0 ack=1 install=0 pairwise=8
kde_len=0 keyidx=0 encr=0)
IEEE 802.1X: 121 bytes from 00:26:bb:17:f6:61
   IEEE 802.1X: version=1 type=3 length=117
wlan0: STA 00:26:bb:17:f6:61 WPA: received EAPOL-Key frame (2/4 Pairwise)
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state PTKCALCNEGOTIATING
WPA: PTK derivation - A1=00:22:cf:03:e0:30 A2=00:26:bb:17:f6:61
WPA: PMK - hexdump(len=32): [REMOVED]
WPA: PTK - hexdump(len=64): [REMOVED]
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state PTKCALCNEGOTIATING2
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state PTKINITNEGOTIATING
bsd_get_seqnum: addr=00:00:00:00:00:00 idx=1

wlan0: STA 00:26:bb:17:f6:61 WPA: sending 3/4 msg of 4-Way Handshake
WPA: Send EAPOL(version=2 secure=1 mic=1 ack=1 install=1 pairwise=8
kde_len=94 keyidx=1 encr=1)
Plaintext EAPOL-Key Key Data - hexdump(len=104): [REMOVED]
IEEE 802.1X: 99 bytes from 00:26:bb:17:f6:61
   IEEE 802.1X: version=1 type=3 length=95
wlan0: STA 00:26:bb:17:f6:61 WPA: received EAPOL-Key frame (4/4 Pairwise)
WPA: 00:26:bb:17:f6:61 WPA_PTK entering state PTKINITDONE
bsd_set_key: alg=CCMP addr=00:26:bb:17:f6:61 key_idx=0

bsd_set_sta_authorized: addr=00:26:bb:17:f6:61 authorized=1

wlan0: STA 00:26:bb:17:f6:61 IEEE 802.1X: authorizing port
wlan0: STA 00:26:bb:17:f6:61 RADIUS: starting accounting session
4BDEE104-00000000
bsd_sta_clear_stats: addr=00:26:bb:17:f6:61

wlan0: STA 00:26:bb:17:f6:61 WPA: pairwise key handshake completed (RSN)
...

thanks a bunch again,

Ganbold


> Thanks.
> AK
>
>
>
>   


-- 
Every Horse has an Infinite Number of Legs (proof by intimidation):
Horses have an even number of legs. Behind they have two legs, and in
front they have fore-legs. This makes six legs, which is certainly an
odd number of legs for a horse. But the only number that is both even
and odd is infinity. Therefore, horses have an infinite number of legs.
Now to show this for the general case, suppose that somewhere, there is
a horse that has a finite number of legs. But that is a horse of another
color, and by the [above] lemma ["All horses are the same color"], that
does not exist.